Trait sp_std::ops::Add 1.0.0[−][src]
Expand description
The addition operator +
.
Note that Rhs
is Self
by default, but this is not mandatory. For
example, std::time::SystemTime
implements Add<Duration>
, which permits
operations of the form SystemTime = SystemTime + Duration
.
Examples
Add
able points
use std::ops::Add; #[derive(Debug, Copy, Clone, PartialEq)] struct Point { x: i32, y: i32, } impl Add for Point { type Output = Self; fn add(self, other: Self) -> Self { Self { x: self.x + other.x, y: self.y + other.y, } } } assert_eq!(Point { x: 1, y: 0 } + Point { x: 2, y: 3 }, Point { x: 3, y: 3 });
Implementing Add
with generics
Here is an example of the same Point
struct implementing the Add
trait
using generics.
use std::ops::Add; #[derive(Debug, Copy, Clone, PartialEq)] struct Point<T> { x: T, y: T, } // Notice that the implementation uses the associated type `Output`. impl<T: Add<Output = T>> Add for Point<T> { type Output = Self; fn add(self, other: Self) -> Self::Output { Self { x: self.x + other.x, y: self.y + other.y, } } } assert_eq!(Point { x: 1, y: 0 } + Point { x: 2, y: 3 }, Point { x: 3, y: 3 });
Associated Types
Required methods
Implementations on Foreign Types
Panics
This function may panic if the resulting point in time cannot be represented by the
underlying data structure. See SystemTime::checked_add
for a version without panic.
type Output = SystemTime
Implements the +
operator for concatenating two strings.
This consumes the String
on the left-hand side and re-uses its buffer (growing it if
necessary). This is done to avoid allocating a new String
and copying the entire contents on
every operation, which would lead to O(n^2) running time when building an n-byte string by
repeated concatenation.
The string on the right-hand side is only borrowed; its contents are copied into the returned
String
.
Examples
Concatenating two String
s takes the first by value and borrows the second:
let a = String::from("hello"); let b = String::from(" world"); let c = a + &b; // `a` is moved and can no longer be used here.
If you want to keep using the first String
, you can clone it and append to the clone instead:
let a = String::from("hello"); let b = String::from(" world"); let c = a.clone() + &b; // `a` is still valid here.
Concatenating &str
slices can be done by converting the first to a String
:
let a = "hello"; let b = " world"; let c = a.to_string() + b;